[英]How to get sibling tag values in XML using python ElementTree
I've been trying to get the value of the ci-name
element whose sibling RandomAttribute
's value(text) is IMPORTANT.我一直在尝试获取
ci-name
元素的值,其兄弟RandomAttribute
的 value(text) 很重要。 I'm a beginner to python and I'm trying using Python's inbuilt ElementTree.我是 Python 的初学者,我正在尝试使用 Python 的内置 ElementTree。
Here's the sample XML:这是示例 XML:
<state>
<s-name>State 1</s-name>
<district>
<d-name>District 1</d-name>
<city>
<ci-name>City 1</ci-name>
<RandomAttribute>UN- IMPORTANT</RandomAttribute>
</city>
<city>
<ci-name>City 2</ci-name>
<RandomAttribute>NOT SO IMPORTANT</RandomAttribute>
</city>
<city>
<ci-name>City 3</ci-name>
<RandomAttribute>IMPORTANT</RandomAttribute>
</city>
</district>
</state>
Please help me out with this.这个你能帮我吗。
You can access the value with the XPath-1.0 expression您可以使用 XPath-1.0 表达式访问该值
/state/district/city[RandomAttribute='IMPORTANT']/ci-name
Just put this into a Python XML processor.只需将其放入 Python XML 处理器即可。
In lxml
this can look like在
lxml
这看起来像
xml = ...
tree = etree.parse(xml)
result = tree.xpath('/state/district/city[RandomAttribute='IMPORTANT']/ci-name')
print(result[0].tag)
Output should be输出应该是
City 3
城市3
Not a solution in one line like the previous one, but I like to keep track of how the XML is structured.不像上一个解决方案在一行中解决,但我喜欢跟踪 XML 的结构。
Maybe this helps you understand how ElementTree works?也许这有助于您了解 ElementTree 的工作原理?
import xml.etree.ElementTree as ET
xml = 'temp.xml'
xmltree = ET.parse(xml)
cities = xmltree.findall('district')[0].findall('city')
for city in cities:
RandAttribute = city.findall('RandomAttribute')[0].text
if RandAttribute == "IMPORTANT":
ci_name = city.findall('ci-name')[0].text
print(ci_name)
import lxml.etree as etree
if xml you are taking about is string then如果您正在使用的 xml 是字符串,那么
xml_xpath = "/state/district/city[RandomAttribute='IMPORTANT']/ci-name/text()"
XML_dom = etree.XML(xml)
XML_XPATH_name = etree.XPath(xml_xpath)
return XML_XPATH_name(XML_dom)
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