为什么我在下面的代码中只获得数组“行”中的第一行值。 我需要与查询对应的所有值

Question

  $s = $conn->prepare($q);
  $s->execute([$tagIdValue]);
  $d = $s->fetchAll();
  return $d;

function x($d) {
    foreach ($d as $row) {
      $val = $row["id"];
      $cont = trimContent($row);
      return $row;
    }
  }

i have a query, which returns all the values in the table and a function to convert it into an assosiate array. But only getting the first row in the array

Answer 1

Because ur using return inside loop, it only take first value and return it.

  $s = $conn->prepare($q);
  $s->execute([$tagIdValue]);
  $d = $s->fetchAll();
  return $d;

function x($d) {
    $arr =[]
    foreach ($d as $row) {
      $val = $row["id"];
      $cont = trimContent($row);
      array_push($arr, $val)
    }
   return $arr;
  }

Answer 2

Put your return outside the loop so only it returns only the first loop

function x($d) {
   foreach ($d as $row) {
     $val = $row["id"];
     $cont = trimContent($row);
     return $row;
}
}

Answer 3

Because, you are returning the result set in the loop.

So, only the first row is returned from the loop.

As, in the first iteration, return statement is encountered, so, that function will return and control will get out of the function.

And next iterations will not loop over the result set.

We need to create an array before loop,

append results to that array

and return the array.

Corrected Code:

$s = $conn->prepare($q);
  $s->execute([$tagIdValue]);
  $d = $s->fetchAll();
  return $d;

function x($d) {
 $array = array();
    foreach ($d as $row) {
      $val = $row["id"];
      $cont = trimContent($row);
       $array[] = $row;
    }
 return $array;
}

Answer 4

Instead writing a return inside a loop, replace that line with an array push or array shift function.

Once the loop has ended return the final result obtained from array_push/array_shift.

Answer 5

You need to return outside the loop:

$s = $conn->prepare($q);
$s->execute([$tagIdValue]);
$d = $s->fetchAll();
return $d;

function x($d) {
  $arr =array();
  foreach ($d as $k=> $row) {
    $val = $row["id"];
    $cont = trimContent($row);
    $arr[$k] = $row;
  }
  return $arr;
}