如何使用 while 循环创建 3 的倍数的 python 程序

Question

ok first sorry if my english is bad

i want to ask how to create python programs multiple of 3 with while loop, like this:

i=0
while i < 10:
   i += 1
   if i == 3:
     continue
   print(i)

output:
1
2
4
5
6
7
8
9
10

so i want to eliminate the number 3 6 9, can anyone help me? i newbie:'v thanks.

Answer 1

It seems as if you want to print the numbers in reverse order (backwards/upside-down), so here is the snippet of code to achieve that task:

i=10
while i > 0:
   if i%3 != 0:
     print(i)
   i-=1

The value of 'i' is the number which it will start counting down from.

Answer 2

i=0
while i < 10:
   i += 1
   if i % 3 == 0:
     continue
   print(i)