如何从laravel 6的数据库中的数组中删除/更新单个值？

Question

Currently I have a column called userIds in my database which is an array. I want to be able to update/remove a single value from that array but the methods I have tried has not worked.

Controller

public function removeUser(Request $request) {
     $scrumId = $request->scrumId;
     $userId = $request->userId;

     DB::table('scrumboards')->where('userIds', $userId)->delete();

     return redirect()->back();
}

How would I be able to update a single value from an array from the database without removing the entire column?

--EDIT--

DB row example:

title    UserIds
test     ["1"]

Answer 1

It's really bad idea to use userIds . If your scrumboards datas become huge.

It will become so slow when find the scrumboards with userid .

Recommended:

so Why don't you use hasMany or many-to-many relationship, like Scrumboard has many Users

and if your datas become huge, you can add index to scrumboard_id ,

Scrumboard Model:

class Scrumboard extends Model {
    protected $table = 'scrumboards';
    public function users()
    {
        return $this->hasMany(User::class, 'scrumboard_id', 'id');
    }
}

User Model:

class User extends Model {
    protected $table = 'users';
    public function scrumboard()
    {
        return $this->belongsTo(Scrumboard::class, 'scrumboard_id');
    }
}

and then you can delete like this:

User::where('id', $userId)->delete();
# or
User::where('id', $userId)->update(['scrumboard_id' => null]);

Not Recommended:

If you really want to use user_ids, you can do it like this: (find the user_id by like , update it to empty by replace )

$sb = DB::table('scrumboards')->where('userIds', 'like', "%\"{$userId}\"%");
$sb->update(['userIds' => \DB::raw("REPLACE(userIds, '\"{$userId}\"', '')")]);