在 Swift 中调用的 C 结构在调用本机代码时不会更新

Question

I have a C Struct:

 struct FastSax { 
        int parseErrorType;
        int parserStatus;
        int cacheIndex;
        char* input;
        int (* findOpen)(FastSax *, int);
        int (* findClose)(FastSax *, int); 
        void (* print)(char *);
        char* (* parse)(FastSax* , const char*); 
    };

Initialized like this:

FastSax* getDefault() {

    FastSax *sax = malloc(sizeof (FastSax));
    sax->cacheIndex = -1;


    sax->findOpen = &findOpen;
    sax->findClose = &findClose;
    sax->parse = & parse;
    sax->hasMoreTokens = &hasMoreTokens;
    sax->fetchNextToken = &fetchNextToken;
    sax->print = &print;


    sax->parseErrorType = PARSE_ERROR_NONE;
    sax->parserStatus = PARSE_STATUS_INSUFFICIENT_DATA;

    sax->input = malloc(50 * sizeof (char));

    strncpy(sax->input, "", 10);
    sax->input[strlen(sax->input)] = '\0';


    return sax;

}

I am calling the parse function in a loop that processes lines from a file. The parse function runs and based on its output, updates some properties of the struct object.

     char* parse(FastSax* fs , const char *freshData) {

       //parse operations on freshData
fs.cacheIndex = strlen(freshData);
fs.parserStatus = 4;


    /**Parser code here**/


//not a constant string
return "the-result-of-the-parse";
    }

In Swift, I do:

class ParserClient{
    let fastSax = getDefault()


 func parse(line: String) -> Int{

        let ptr = fastSax

        var status:Int32 = -1

        let fs: FastSax = ptr!.withMemoryRebound(to: FastSax.self, capacity: 1) {
            $0.pointee
        }

        let out = fs.parse(ptr , line)


        //consume the first token
        if fs.parseErrorType == PARSE_ERROR_NONE{
            var token = String(cString: out)
            self.delegate.endEntry(entry: token)

            while true {
                var _token = String(cString: fs.parse(ptr ,""))

                Log.out("\(_token) , parser-status: \(fs.parserStatus)")

                if fs.parserStatus == PARSE_STATUS_OK {
                    self.delegate.endEntry(entry: _token)
                }else{
                    break
                }

            }

        }else{
            Log.out("Error: parser-status: \(fs.parserStatus) , error-type: \(fs.parseErrorType)")
        }

        return Int(fs.parserStatus)
    }

}

When the parser code is invoked in C, it works fine.

But when called from Swift, I noticed that the struct object ie fs properties were not being updated on each iteration of the while loop.

Question:

How do I make sure that the struct's properties are updated when it calls C code.

Is the copy of the struct invoked from Swift different from the one being used by C?

Answer 1

Is the copy of the struct invoked from Swift different from the one being used by C?

Exactly. This

let fs: FastSax = ptr!.withMemoryRebound(to: FastSax.self, capacity: 1) {
    $0.pointee
}

is a (complicated) way of making a copy of the struct pointed to by ptr . Then

let out = fs.parse(ptr , line)

updates the structure pointed to by ptr (which is the default structure obtained before) and not the structure pointed to by fs .

What you probably want is simply

let out = fastSax!.pointee.parse(fastSax, line)

assuming that fastSax is not nil . Use optional binding or optional chaining if that is not guaranteed. The ptr and fs variables are not needed.