如何循环遍历具有特定条件的对象并返回其值的数组？

Question

I have an array of all items ids:

const allIds = ['a1gb', 'f4qa', 'i9w9']

I also have an object with it's properties having those ids as keys:

const byId = {
  a1gb: {
    whatever1
  },
  anyOtherIdThatIDontNeed: {
    whatever444
  },
  f4qa: {
    whatever2
  },
  i9w9: {
    whatever3
  }
}

What is the most common way to return an array that would look like

[ { whatever1 }, { whatever2 }, { whatever3 } ]

and skip the Ids I don't want in my final array?

This a log of the array with the ids:

This is a log of the object from which I need to return an array with the values of the keys from that array of ids skipping the ones I don't need:

PS Problem is that in that return array from the map function I get undefined when it encounters "anyOtherIdThatIDontNeed:".

PPS[ ANSWER ] - The array of Ids had ids that do not match object's keys and that is why I was getting undefined.

Answer 1

var result = allids.map(val => ({byId[val]}))

I would suggest this way, try the below code if the array also has unwanted ids.

var result = allids.map(val => ({byId[val]})).filter(val => val?true:false)