Python正则表达式替换以特定短语开头和结尾的文本

Question

I want to replace text starting with <img> and ending with </img> . Im just starting with regex stuff.

I have tried below code.

Final result should be:

input:

"New Year's Eve <img>scr=[...]</img>, New Year's Day (Observed)"

output:

"New Year's Eve [image placeholder], New Year's Day (Observed)"

Code sample

import re
input = [
    "Independence Day (Observed)",
    "Another Christmas Eve, Christmas Day (Observed)",
    "New Year's Eve <img>scr=[...]</img>, New Year's Day (Observed)",
    "Martin Luther King, Jr. <img>scr=[...]</img> Day"
]
for holiday in input:
    print(re.sub(r'\b<img>\b', '[image placeholder]', holiday))`

Answer 1

You want to replace all the code between the opening and closing tag:

import re
input = [
    "Independence Day (Observed)",
    "Another Christmas Eve, Christmas Day (Observed)",
    "New Year's Eve <img>scr=[...]</img>, New Year's Day (Observed)"
    "Martin Luther King, Jr. <img>scr=[...]</img> Day"
]
for holiday in input:
    print(re.sub(r'<img>.*?</img>', '[image placeholder]', holiday))

Output:

Independence Day (Observed)
Another Christmas Eve, Christmas Day (Observed)
New Year's Eve [image placeholder], New Year's Day (Observed)
Martin Luther King, Jr. [image placeholder] Day

The regex matches text starting with <img> and ending with </img> with anything in between .*? . ? makes it match non greedily, so that it will match until the first closing tag that follows the opening tag - that allows it to replace every pair of tags correctly if there are several in the same input text.