使用powershell在.txt文件中查找出现次数最多的字符串

Question

I'm currently working on a school assignment in powershell and I have to display the word longer then 6 characters with the most occurences from a txt file. I tried this code but it's returning the number of occurrences for each word and it's not what i need to do. Please help.

$a= Get-Content -Path .\germinal_split.txt
foreach($object in $a) 
{
if($object.length -gt 6){
$object| group-object | sort-object -Property "Count" -Descending | ft -Property ("Name", "Count");
}
 }

Answer 1

From the question we don't know what's in the text file. The approaches so far will only work if there's only 1 word per line. I think something like below will work regardless:

$Content = (Get-Content 'C:\temp\test12-01-19' -raw) -Split "\b"

$content | 
Where-Object{$_.Length -ge 6} |
Group-Object -Property Length -NoElement | Sort-Object count | Format-Table -AutoSize

Here I'm reading in the file as a single string using the -Raw parameter. Then I'm splitting on word boundaries. Still use Where to filter out words shorter than 6 characters. Now use Group-Object against the length property as seen in the other examples.

I don't use the word boundary RegEx very often. My concern is it might be weird around punctuation, but my tests look pretty good.

Let me know what you think.

Answer 2

You can do something like the following:

$a = Get-Content -Path .\germinal_split.txt
$a | Where Length -gt 6 | Group-Object -NoElement | Sort-Object Count -Descending

Explanation:

Where specifies the Length property's condition. Group-Object -NoElement leaves off the Group property, which contains the actual object data. Sort-Object sorts the grouped output in ascending order by default. Here the Count property is specified as the sorted property and the -Descending parameter reverses the default sort order.