PHP / MySQL：来自 MySQL 的数据未显示在选择选项（下拉列表）中

Question

I created a dropdown list where all the data is populated from a column in a MySQL database table. The problem is, the data is not displayed. I don't know why. Below is my code:

PHP

<?php
//getting id from url
$badgeid = $_GET['badgeid'];

//selecting data associated with this particular id
$sql = "SELECT * FROM users LEFT JOIN roles on users.roles_id = roles.roles_id LEFT JOIN team on users.team_id = team.team_id WHERE badgeid = :badgeid";
$query = $conn->prepare($sql);
$query->execute(array(':badgeid' => $badgeid));

while($row = $query->fetch(PDO::FETCH_ASSOC))
{
  $badgeid = $row["badgeid"];;
  $fullname = $row["fullname"];
  $roles_id = $row["roles_id"];
  $roles_name = $row["roles_name"];
  $team_id = $row["team_id"];
  $team_name = $row["team_name"];
}

?>

html

<tr>
  <td width="20%"><b>Team</b></td>
  <td width="80%">
    <select class="form-control" id="exampleFormControlSelect1" name="team_name">
    <?php echo "<option value='".$row["team_name"]."'>".$row["team_name"]."</option>"; ?>
    </select>
  </td>
</tr>

Answer 1

change in php at while loop like this,

<?php
//getting id from url
$badgeid = $_GET['badgeid'];

//selecting data associated with this particular id
$sql = "SELECT * FROM users LEFT JOIN roles on users.roles_id = roles.roles_id LEFT JOIN team on users.team_id = team.team_id WHERE badgeid = :badgeid";
$query = $conn->prepare($sql);
$query->execute(array(':badgeid' => $badgeid));
$rows = $query->fetchAll(PDO::FETCH_ASSOC);
foreach($rows as $row)
{
  $badgeid[] = $row["badgeid"];;
  $fullname[] = $row["fullname"];
  $roles_id[] = $row["roles_id"];
  $roles_name[] = $row["roles_name"];
  $team_id[] = $row["team_id"];
  $team_name[] = $row["team_name"];
}

?>

you are directly fetch in while loop , so it skipping first row , so you have not no data in $row . And also use fetchAll() so it fetch all row of table . fetch() only one row.