使用区分大小写字符的正则表达式拆分字符串上的名称

Question

I want to split names into array with these kind of string.

Bol BolLouis King
Brandon ClarkeRui Hachimura
Michael Jeffery JordanDennis Rodman

to

['Bol Bol', 'Louis King']
['Brandon Clarke', 'Rui Hachimura']
['Michael Jeffery Jordan', 'Dennis Rodman']

I have already retied creating my own regex using ^[AZ]\\w+\\s[AZ][az]+ but this only matches the first name and i can't capture the 2nd or 3rd name. I'm also having some issues when the name has 3 words on it like Michael Jeffery Jordan

Answer 1

I would suggest making use of a positive lookahead to be able to generalize your pattern. That allows you to match an expression that is immediately followed by some other expression. Use a (?=someRegexp) at the end of your pattern to make the end be the case where a lowercase character is immediately followed by an uppercase one. You can then generalize to any number of words.

I would also suggest splitting it into two cases then, as the last name in your expression wouldn't be followed by a capital letter but rather by a end of string character. You can do that with an or: (someRegexp|someOtherRegexp)

Answer 2

你没有说你想要这个，所以这里有一个 sed 版本，它适用于你的示例输入：

sed -e "s/\\(.*[az]\\)\\([AZ].*\\)/['\\1', '\\2']/g"

Answer 3

As not all browsers support lookbehind, here is a solution without:

 var test = [ 'Bol BolLouis King', 'Brandon ClarkeRui Hachimura', 'Michael Jeffery JordanDennis Rodman', ]; console.log(test.map(function (a) { // return a + ' :' + a.match(/\\b[az]{1,2}\\K\\s/); return a.match(/^(.+?[az])([AZ].+)/); }));