[英]type 'Future<List<Data>>' is not a subtype of type 'List<Data>' in type cast
I am getting the data from server and trying to set it in a grid view but I am getting error:我正在从服务器获取数据并尝试将其设置在网格视图中,但出现错误:
type 'Future<List<Data>>' is not a subtype of type 'List<Data>' in type cast
Here is my Data Class:这是我的数据类:
class Data with ChangeNotifier {
Data({
this.name,
this.image,
});
final String image;
final String name;
factory Data.fromJson(Map<String, dynamic> json) {
print(json['title'].toString());
return Data(
name: json['title'].toString(),
image: json['image'].toString(),
);
}
}
And this is my Data_screen where I am calling this:这是我的 Data_screen,我在那里调用它:
var datas= Provider.of<Datas>(context).fetchData() as List<Data>;
var datalength = datas.length;
Widget:小部件:
Expanded(
child: GridView.builder(
gridDelegate: SliverGridDelegateWithFixedCrossAxisCount(
crossAxisSpacing: 10,
mainAxisSpacing: 10,
),
padding: EdgeInsets.only(left: 28, right: 28, bottom: 58),
itemCount: datas.length,
itemBuilder: (context, index) => DataCard(
datas[index],
index: index,
onPress: () {
},
),
),
),
And in Datas.dart:在 Datas.dart 中:
Future<List<Data>> fetchData() async {
var response = await http.get(url);
var responseJson = json.decode(response.body);
print(responseJson);
return (responseJson['datas'])
.map<Data>((p) => Data.fromJson(p))
.toList();
} }
The message is so clear.信息如此清晰。 You cannot cast from List<Data>
to Future<List<Data>>
.您不能从List<Data>
为Future<List<Data>>
。 Try to use:尝试使用:
List<Data> fetchData() async {
var response = await http.get(url);
var responseJson = json.decode(response.body);
print(responseJson);
return (responseJson['datas'])
.map<Data>((p) => Data.fromJson(p))
.toList();
}
OR return a new Future
with the List<Data>
或者用List<Data>
返回一个新的Future
Future<List<Data>> fetchData() async {
var response = await http.get(url);
var responseJson = json.decode(response.body);
print(responseJson);
var response = (responseJson['datas'])
.map<Data>((p) => Data.fromJson(p))
.toList();
return Future.value(response)
}
It just an idea(without testing)这只是一个想法(未经测试)
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