Bash 脚本如何逐个显示文件名

Question

I make file "my.sh" and in the file I write code

if [ $# = 0 ]; then
   echo "filename: $0"
fi

and I execute my.sh file

$ my.sh -> I want output [ filename: my.sh ]

however, the result shows [ filename: ./my.sh ]

I finally want when I enter my.sh , the output shows [ filename: my.sh ] and when I enter ./my.sh , the output shows [ filename: ./my.sh ]

Answer 1

You could use basename :

#!/usr/bin/env bash
if [ $# = 0 ]; then
   echo $(basename $0)
fi

Also, take a note that [[ is generally safer to use .