[英]PowerShell dot reference XML attribute
Given a single XML node like this给定一个这样的 XML 节点
<MachineLogFileName overwrite="[bool]"></MachineLogFileName>
and assigned to a variable like this并分配给这样的变量
$validationNode = $validation.xml.SelectSingleNode("//Settings/$($node.name)")
where of course $node.name
is 'MachineLogFileName'
, and a variable $attribute.name
of 'overwrite'
, I want to be able to get the value of that attribute, but only as an attribute.当然
$node.name
是'MachineLogFileName'
,变量$attribute.name
是'overwrite'
,我希望能够获得该属性的值,但只能作为一个属性。 I can use $validationNode.($attribute.name)
, but IF there was a child node called <overwrite>
and wasn't an attribute called 'overwrite'
I would end up getting the inner text of the child node.我可以使用
$validationNode.($attribute.name)
,但是如果有一个名为<overwrite>
的子节点而不是一个名为'overwrite'
的属性,我最终会得到子节点的内部文本。 So in a sense I want something like $validationNode.Attributes.($attribute.name)
.所以从某种意义上说,我想要类似
$validationNode.Attributes.($attribute.name)
。 It seems like there is a collection there, with a single attribute in this case, but I can't seem to get the value this way.似乎那里有一个集合,在这种情况下只有一个属性,但我似乎无法通过这种方式获得该值。 Ultimately this needs to work with highly variable attribute and child node names, and I could just loop through all the attributes, but I need this in an IF so something like
$validationNode.Attributes.($attribute.name)
would be ideal.最终这需要使用高度可变的属性和子节点名称,我可以循环遍历所有属性,但我需要在 IF 中使用它,因此像
$validationNode.Attributes.($attribute.name)
这样的东西将是理想的。 And seems like it should be possible and I am just missing one aspect?似乎应该有可能,而我只是错过了一个方面? I hope.
我希望。
I want to be able to get the value of that attribute, but only as an attribute.
我希望能够获得该属性的值,但只能作为一个属性。 I can use
$validationNode.($attribute.name)
, but IF there was a child node called<overwrite>
and wasn't an attribute called 'overwrite'我可以使用
$validationNode.($attribute.name)
,但是如果有一个名为<overwrite>
的子节点并且不是一个名为 'overwrite' 的属性
Use GetAttribute()
:使用
GetAttribute()
:
$validationNode = $validation.xml.SelectSingleNode("//Settings/$($node.name)")
$attributeValue = $validationNode.GetAttribute($attribute.name)
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