[英]how to decode Java stream in PHP
I requested Walmart report API and the result would be returned zip file stream.Refer to the API documents,it gives an example to realize it with Java code as the following below:我请求了沃尔玛报表API,返回的结果是zip文件流。参考API文档,给出了一个用Java代码实现的例子,如下:
if (response.getStatus() == Response.Status.OK.getStatusCode() && response.hasEntity()) {
InputStream inputStream = (InputStream)response.getEntity();
try {
String header = response.getHeaderString("Content-Disposition");
if(header != null && !("").equals(header)) {
if(header.contains("filename")){
//header value will be something like:
//attachment; filename=10000000354_2016-01-15T23:09:54.438+0000.zip
int length = header.length();
String fileName = header.substring(header.indexOf("filename="),length);
System.out.println("filenameText " + fileName);
String [] str = fileName.split("=");
System.out.println("fileName: " + str[1]);
//replace "/Users/anauti1/Documents/" below with your values
File reportFile = new File("/Users/anauti1/Documents/" + str[1].toString());
OutputStream outStream = new FileOutputStream(reportFile);
byte[] buffer = new byte[8 * 1024];
int bytesRead;
while ((bytesRead = inputStream.read(buffer)) != -1) {
outStream.write(buffer, 0, bytesRead);
}
IOUtils.closeQuietly(inputStream);
IOUtils.closeQuietly(outStream);
}
}
}
catch (Exception ex){
System.out.print("Exception: " + ex.getMessage());
}
}
However,if I use php like:但是,如果我使用 php 像:
try {
$header = $resultInfo->getHeader('Content-Disposition');
if (!empty($header)) {
if (strpos($header, 'filename') !== false) {
$filename = substr($header, strpos($header, 'filename'));
$str = explode('=', $filename);
$body = $resultInfo->getBody();
$fp = fopen(storage_path("csv/{$str[1]}"), 'w');
fwrite($fp, $body);
fclose($fp);
}
}
} catch (\Exception $e) {
echo $e->getMessage();
}
It would download zip file but the file data is corrupt.It maybe such a reason like the byte stream is transfered by using Java code.It's the problem about how to transform the bytes stream.Could you help me?它会下载zip文件,但文件数据已损坏。这可能是使用Java代码传输字节流之类的原因。这是如何转换字节流的问题。您能帮我吗? By th way,I have cut parts of the stream as the following below:顺便说一句,我已将部分流切割如下:
b"PK\x03\x04\x14\x00\x00\x00\x08\x00\x10`‚OI^\x07RÒƒ\x04\x00Óo\x10\x004\x00\x00\x00ItemReport_10001023965_2019-12-02T115111.5040000.csvì½YsÛÈ–.ú~#î\x7F`ì‡>
Headers like this:像这样的标题:
-headers: array:11 [
"accept-ranges" => array:1 [
0 => "bytes"
]
"content-disposition" => array:1 [
0 => "attachment; filename=ItemReport_10001023965_2019-12-02T115111.5040000.zip"
]
"content-type" => array:1 [
0 => "application/zip"
]
"x-tb" => array:1 [
0 => "0"
]
"expires" => array:1 [
0 => "Wed, 04 Dec 2019 02:33:20 GMT"
]
"cache-control" => array:1 [
0 => "max-age=0, no-cache, no-store"
]
"pragma" => array:1 [
0 => "no-cache"
]
"date" => array:1 [
0 => "Wed, 04 Dec 2019 02:33:20 GMT"
]
"transfer-encoding" => array:1 [
0 => "chunked"
]
"connection" => array:2 [
0 => "keep-alive"
1 => "Transfer-Encoding"
]
"set-cookie" => array:1 [
0 => "TS0d138f181a7bb55a8f02b54ee05b24ba9b4832fa32c8b0a9c4cb8592e5d1e4d02765d16ec77313d435d3ade8; Path=/; Secure"
]
]
-headerNames: array:11 [
"accept-ranges" => "Accept-Ranges"
"content-disposition" => "Content-Disposition"
"content-type" => "Content-Type"
"x-tb" => "X-Tb"
"expires" => "Expires"
"cache-control" => "Cache-Control"
"pragma" => "Pragma"
"date" => "Date"
"transfer-encoding" => "Transfer-Encoding"
"connection" => "Connection"
"set-cookie" => "Set-Cookie"
]
I just found that the transfer-encoding is chuncked.I'm not sure it's this problem?我刚刚发现传输编码被压缩了。我不确定是这个问题吗?
It seems Json Encoded and you Must Decode it with json in php script so: json_decode(string,array) string = your gathered encoded response.似乎 Json 编码,您必须在 php 脚本中使用 json 对其进行解码,因此: json_decode(string,array) string = 您收集的编码响应。 array = True if you want array of result data. array = True 如果你想要结果数据数组。
2- use header('Content-Type: application/json') (this header most useful before sending or recieving response) 2- 使用 header('Content-Type: application/json') (这个头在发送或接收响应之前最有用)
3 -Error handling : json_last_error() json_last_error_msg() 3 - 错误处理:json_last_error() json_last_error_msg()
try {
$header = $resultInfo->getHeader('Content-Disposition');
if (!empty($header)) {
if (strpos($header, 'filename') !== false) {
$filename = substr($header, strpos($header, 'filename'));
$str = explode('=', $filename);
$body = $resultInfo->getBody();
$fp = fopen(storage_path("csv/{$str[1]}"), 'w');
##uncomment below line if response not valid may help you.
# header('Content-Type: application/json');
$dbody = json_decode($body,true);
fwrite($fp, $dbody);
fclose($fp);
}
}
} catch (\Exception $e) {
echo $e->getMessage();
}
Hope to be helpful希望有帮助
Did you resolve the issue?你解决了问题吗? The below simple code worked for me下面的简单代码对我有用
$fp = fopen('/your path where you store the zip file/'.$filename, 'w+');
if ($fp == FALSE){
print "File not opened<br>";
exit;
}
fwrite($fp, $response);
fclose($fp);
$response
is the body of API response, which will be unreadable format $filename
zip filename got from the header. $response
是 API 响应的主体,这将是从标题中获得的不可读格式$filename
zip filename。
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.