我有包含多种方法的类文件，我可以从 Testcase 调用该类吗

Question

I have a class called TestingClass and I have a one more class called TestCase .

In TestingClass I have 4 methods which are dependent on each other, Can i call the this class file from my TestCase file and invoke all the methods at once?

Answer 1

You can try with extend the TestingClass and overwriting those methods as like,

public class TestCase extends TestingClass {
    @Override
    public void method1(){
       super.method1();
    }

    @Override
    public void method2(){
       super.method2();
    }

    @Override
    public void method3(){
       super.method3();
    }

    @Override
    public void method4(){
       super.method4();
    }
 }

Answer 2

Yes you can if they have visibility.

In your TestCase you have to declarate a variable of TestingClass and instantiate it. Then, if your methods are public you can use them.

Here is an example:

public class TestCase {

     private TestingClass testingClass = new TestingClass();

     @Test
     public void test1(){
         testingClass.methodFromTestCase();
     }
}

Answer 3

There is another way to do it, refer below example:

            package overridefunction;
            public class SuperClass 
                {
                public void method1()
                {
                    System.out.println("superclass method1");
                    this.method2();
                    this.method3();
                    this.method4();
                    this.method5();
                }
                public void method2()
                {
                    System.out.println("superclass method2");
                }
                private void method3()
                {
                    System.out.println("superclass method3");
                }
                protected void method4()
                {
                    System.out.println("superclass method4");
                }
                void method5()
                {
                    System.out.println("superclass method5");
                }
            }

        package overridefunction1;
            public class SubClass extends SuperClass
            {
                @Override
                public void method1()
                {
                    System.out.println("subclass method1");
                    super.method1();
                }
            }

            
            package overridefunction1;
            public class Demo 
            {
                public static void main(String[] args) 
                {
                    SubClass mSubClass = new SubClass();
                    mSubClass.method1();
                }
            }

            subclass method1
            superclass method1
            superclass method2
            superclass method3
            superclass method4
            superclass method5