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树莓派 Node.js GPIO 控制

[英]Raspberry Pi Node.js GPIO control

I'm trying to command two motors connected with a l298n module from a RPI4.我正在尝试从 RPI4 命令两个与 l298n 模块连接的电机。 This is not working on node.js but the same script (sort of porting) in python works because motors run.这不适用于 node.js,但 python 中的相同脚本(某种移植)可以工作,因为电机运行。

Python script: Python 脚本:

import RPi.GPIO as GPIO
from time import sleep

in1 = 24
in2 = 23
en = 25

GPIO.setmode(GPIO.BCM)
GPIO.setup(in1,GPIO.OUT)
GPIO.setup(in2,GPIO.OUT)
GPIO.setup(en,GPIO.OUT)
GPIO.output(in1,GPIO.LOW)
GPIO.output(in2,GPIO.LOW)
p=GPIO.PWM(en,1000)
p.start(25)

while(1):
    GPIO.output(in1,GPIO.HIGH)
    GPIO.output(in2,GPIO.LOW)

JS script (maybe not interesting, launched with sudo): JS 脚本(可能没意思,用 sudo 启动):

var Gpio = require('pigpio').Gpio;

const in1 = new Gpio(24, {mode: Gpio.OUTPUT});
const in2 = new Gpio(23, {mode: Gpio.OUTPUT});
const en = new Gpio(25, {mode: Gpio.OUTPUT});

in1.digitalWrite(0);
in2.digitalWrite(0);
en.pwmWrite(255);
setTimeout(function(){ console.log("finish"); }, 10000);

pigpiod -v gives me version 71 pigpiod -v 给我版本 71

Where is the problem?问题出在哪里? (PS: i started with https://www.npmjs.com/package/motor-l298n but when found that motors were not working i tried to go directly with pigpio). (PS:我从https://www.npmjs.com/package/motor-l298n开始,但当发现电机不工作时,我试图直接使用 pigpio)。 The project is in JS so python script is just to check that things works.该项目是在 JS 中,所以 python 脚本只是为了检查事情是否有效。 Thanks谢谢

this code works:此代码有效:

const Gpio = require('pigpio').Gpio;

const in1 = new Gpio(24, {mode: Gpio.OUTPUT});
const in2 = new Gpio(23, {mode: Gpio.OUTPUT});
const en = new Gpio(25, {mode: Gpio.OUTPUT});

let dutyCycle = 0;
in1.digitalWrite(1);
    in2.digitalWrite(0);
setInterval(() => {
    en.pwmWrite(dutyCycle);

dutyCycle += 5;
if (dutyCycle > 255) {
    dutyCycle = 0;
}
}, 20);

so i'm gonna work on it所以我要努力

I believe that the error here is that both in1.digitalWrite(0) and in2.digitalWrite(0) have value of zero.我认为这里的错误是 in1.digitalWrite(0) 和 in2.digitalWrite(0) 的值为零。 The correct approach is that one should have the value of one: in1.digitalWrite(1);正确的做法是one的值应该是one:in1.digitalWrite(1); and in2.digitalWrite(0);和 in2.digitalWrite(0); OR in1.digitalWrite(0);或 in1.digitalWrite(0); and in2.digitalWrite(1);和 in2.digitalWrite(1);

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