雪花 SQL 正则表达式

Question

I am trying to identify a value that is nested in a string using Snowflakes regexp_substr()

The value that I want to access is in quotes:

...
Type:
value: "CategoryA"
...

Edit: This text is nested in a much larger portion of text.

I want to extract CategoryA for all columns using regexp_substr. But I am unsure how. I have tried:

regexp_substr(col, 'Type\\W+(\\w+)\\W+\\w.+')

and while that gives the portion of the string, I just want what is in quotes and can't figure out how to do so.

Answer 1

You could use regexp_replace() instead:

regexp_replace(col, '(^[^"]*")|("[^"]*$)", '')

The regexp matches on both following conditions, and replaces matching parts with the empty string:

• ^[^"]*" : everything from the beginning of the string to the first double quote

• ("[^"]*$)" : everything from the last double quote to the end of the string