为什么 SongName[i]!= null 在它应该是 F 时评估为 T

Question

I need to split the given array and print the string w/o WUB. Below should print "ABC" but instead prints ",,ABC". To be able to print ",,ABC" it needs to satisfy condition songName[i]!= null which should return F for those cases. Still new to Java and programming at all

import java.util.Arrays;

class Main {
  public static void main(String[] args) {

    String SongDecoder = "";
    String song = "WUBWUBABCWUB";
    String[] songName = song.split("WUB");
    int cnt=0;


    for (int i = 0; i < songName.length; i++){
      if (songName[i]!= null){
        if(cnt == 0){
          SongDecoder = songName[i];
          cnt+=1;
        } else {
        SongDecoder = SongDecoder+","+songName[i];
        }
      }
    }

System.out.println(SongDecoder);
System.out.println(Arrays.toString(songName));
  }
}

Answer 1

split() returns empty String s when there are no characters between two separators, not null.

Therefore, you should check for empty String s in addition to your null check:

if (songName[i]!= null && !songName[i].isEmpty())

Or, actually, in this case, it would be enough to check that the String is not empty (since it can't be null):

if (!songName[i].isEmpty())