读取文件时打印随机字符

Question

I have a config.txt file that looks like this:

2
2
[3, 8]
[4, 2]-[12, 7]
[1, 10]-[12, 1]

And I am trying to read its content to process later. However, when I was trying my program and printing the file content it ouputs more characters than are in the file, even when I terminate the string myself. It's like the length of the file is overestimated by the program. This is the output of the printf:

2
2
[3, 8]
[4, 2]-[12, 7]
[1, 10]-[12, 1]df

Obviously the two characters df should not be there. What am I doing wrong. I googled around but I can't find a clear answer. This is my C program:

#include <stdio.h>
#include <stdlib.h>

void readFile(const char *fileName, char *text);

void readFile(const char *fileName, char *text)
{
    FILE *f;
    long length;

    f = fopen(fileName, "r");
    fseek (f, 0, SEEK_END);
    length = ftell (f);
    fseek (f, 0, SEEK_SET);
    text = malloc(length + 1);
    if(text)
    {
        fread (text, 1, length, f);
    }
    fclose (f);
    text[length] = '\0';

    printf(text);
}

int main(void)
{
    char *fileText;
    readFile("config.txt", fileText);

    return 1;
}

Answer 1

就像user3121023已经建议的那样，在 fopen 语句中将“r”更改为“rb”解决了这个问题。