获取某些目录和子目录中所有文件的部分路径

Question

I am retrieving all files using Illuminate\\Support\\Facades\\File :

    $files = File::allFiles(base_path('resources/views/emails'));
    foreach($files as $file) {
        $file_name = $file->getBasename('.blade.php');
        $path_info = $file->getPathInfo();

        $template = substr($path_info, strpos($path_info, 'emails/') + 7).'.'.$file_name;
        $template = str_replace('/', '.', $template);
    }

Inside emails directory there are more subdirectories with some containing another directory inside. I would like to get all file names, without extension, but with names of subdirectories the file is stored in. I would also like to omit everything before emails directory (including emails itself) from path name.

Example: resources/views/emails/subfolder_one/subfolder_two/myfile.blade.php

Expected output: subfolder_one.subfolder_two.myfile

The way I did it works, but seems too complicated. Is there a function which would reduce number of lines of code withing foreach loop?

Answer 1

if it's always your folder start from emails you may explode the path to the array and for loop at index 3 and concatenate result with "."

$str = 'resources/views/emails/subfolder_one/subfolder_two/myfile.blade.php';
$str_arr = explode('/', $str);
$template = '';
for ($i = 3; $i < count($str_arr); $i++) {
    $template .= $str_arr[$i] . '.';
}
dd($template);