如何从html表单读取RSS提要
[英]How to read rss feed from html form
问题描述
I am trying to build an HTML/PHP application where you type in an RSS URL into a form field and then retrieve the RSS feed in the browser as a result of going to the rssfeed.php page.
我正在尝试构建一个 HTML/PHP 应用程序，您可以在其中将 RSS URL 输入到表单字段中，然后作为转到 rssfeed.php 页面的结果在浏览器中检索 RSS 提要。 Currently, I am getting an error file_get_contents() expects parameter 1 to be a valid path, array given in C:\\xampp\\htdocs\\week14\\rssfeed.php on line 2目前，我收到一个错误file_get_contents() expects parameter 1 to be a valid path, array given in C:\\xampp\\htdocs\\week14\\rssfeed.php on line 2
Here is my index.html code:这是我的 index.html 代码：
<html>
<body>
<form action="rssfeed.php" method="post">
Please enter the RSS feed URL: <input type="content" name="name"><br>
<input type="submit">
</form>
</body>
</html>
Here is the rssfeed.php code:这是 rssfeed.php 代码：
<?php
$content = file_get_contents($_POST);
?>
Not even sure what to google anymore, I am new to building code from scratch.甚至不确定要谷歌什么，我是从头开始构建代码的新手。
So this is what displays a feed from espn but I need to integrate this so that when I type the URL into the form it places that one into the place where the url in this code snippet currently is:所以这就是显示来自 espn 的提要的内容，但我需要将其集成，以便当我在表单中键入 URL 时，它将该 URL 放置到此代码片段中当前的 URL 所在的位置：
$feed_url = "http://rssfeeds.usatoday.com/UsatodaycomGolf-TopStories";
$content = file_get_contents($feed_url);
$x = new SimpleXmlElement($content);
echo '<ul>';
foreach($x->channel->item as $entry) {
echo '<li>';
echo '<a href="'.$entry->link.'" title="'.$entry->title.'" target="_blank">' . $entry->title . '</a>'; // output link & title
echo $entry->description; // return post content
echo '</li>';
}
echo "</ul>";
2 个解决方案
解决方案1
1 2019-12-10 15:58:49
To give an idea how you can POST a url for some RSSFeed to a script and then process it perhaps this might help.要了解如何将某些RSSFeed的 url 发布到脚本然后对其进行处理，这可能会有所帮助。
To process the contents of an RSSFeed typically one would use DOMDocument or SimpleXML - the code here simply loads the remote XML file directly into the DOMDocument and instantiates an XPath object to further query to find nodes.要处理 RSSFeed 的内容，通常会使用DOMDocument或SimpleXML - 这里的代码只是将远程 XML 文件直接加载到DOMDocument并实例化一个 XPath 对象以进一步查询以查找节点。 There are many other ways one could do this - but it was quickly written just as example.有许多其他方法可以做到这一点 - 但它很快就被写成了例子。
<html>
<head>
<title>RSS</title>
</head>
<body>
<form method='post'>
<input type='text' name='name' value='https://www.huffingtonpost.co.uk/feeds/index.xml' />
<input type='submit'>
</form>
<?php
if( $_SERVER['REQUEST_METHOD']=='POST' && !empty( $_POST['name'] ) ){
$dom=new DOMDocument;
$dom->load( $_POST['name'] );
$xp=new DOMXPath( $dom );
$col=$xp->query( '//channel/item' );
if( $col->length > 0 ){
foreach( $col as $node ){
printf(
'<h3>%s</h3>',
$xp->query('title',$node)->item(0)->textContent
);
}
}
}
?>
</body>
</html>
a snippet from the output:输出中的一个片段：
<h3>Where To Travel In 2020: The Top 10 Emerging Destinations</h3>
<h3>Gavin And Stacey Christmas Special: First Reviews Of Reunion Episode Are In</h3>
<h3>Jeremy Corbyn Speaks To The Common People | The People's Election</h3>
A more complete example showing multiple possible RSS feeds and more fields from each article:一个更完整的示例，显示了每篇文章中多个可能的 RSS 提要和更多字段：
<html>
<head>
<title>RSS</title>
</head>
<body>
<form method='post'>
<select name='name'>
<optgroup label='World news'>
<option>http://rssfeeds.usatoday.com/UsatodaycomGolf-TopStories
<option>http://feeds.reuters.com/Reuters/worldNews
<option>http://rss.cnn.com/rss/edition_world.rss
</optgroup>
<optgroup label='UK news'>
<option>http://feeds.bbci.co.uk/news/rss.xml
<option>http://feeds.skynews.com/feeds/rss/uk.xml
<option>http://feeds.reuters.com/reuters/UKdomesticNews
</optgroup>
<optgroup label='US news'>
<option>http://rssfeeds.usatoday.com/usatoday-newstopstories
<option>http://feeds.reuters.com/Reuters/domesticNews
<option>http://feeds.skynews.com/feeds/rss/us.xml
</optgroup>
<optgroup label='Miscellaneous'>
<option>https://www.wired.com/feed
<option>http://rss.slashdot.org/Slashdot/slashdot
<option>https://www.huffingtonpost.co.uk/feeds/index.xml
</optgroup>
</select>
<input type='submit'>
</form>
<?php
if( $_SERVER['REQUEST_METHOD']=='POST' && !empty( $_POST['name'] ) ){
$url=$_POST['name'];
$max=150;
$ellipsis=str_repeat('.',5);
$dom=new DOMDocument;
$dom->load( $url );
$xp=new DOMXPath( $dom );
$col=$xp->query( '//channel/item' );
if( $col->length > 0 ){
echo '<ul>';
foreach( $col as $node ){
try{
$description=$xp->evaluate('string(description)',$node);
if( strlen( $description ) > $max )$description=substr( $description, 0, $max ) . $ellipsis;
$category=$xp->evaluate( 'string(category)', $node );
printf(
'<li>
<a href="%s" target="_blank">%s</a>
<div>Category: %s</div>
<p>%s</p>
</li>',
$xp->evaluate( 'string(link)', $node ),
$xp->evaluate( 'string(title)',$node ),
$category,
$description
);
}catch( Exception $e ){
continue;
}
}
echo '</ul>';
} else {
echo 'nothing found for given XPath query';
}
}
?>
</body>
</html>
解决方案2
0 2019-12-11 03:32:17
Granted this only reads http links not https:当然，这只会读取 http 链接而不是 https：
Index.html:索引.html：
<!DOCTYPE html>
<html>
<head>
<link rel="stylesheet" href="styles.css" type="text/css">
<title>RSS Feed Search</title>
</head>
<body>
<h2>RSS Search</h2>
<form form action="rss.php" method="post">
<input type='text' name='name' value='' />
<input type='submit'>
</form>
</body>
</html>
rss.php: rss.php：
<?php
if( $_SERVER['REQUEST_METHOD']=='POST' && !empty( $_POST['name'] ) ){
$feed_url = ( $_POST['name'] );
$content = file_get_contents($feed_url);
$x = new SimpleXmlElement($content);
echo '<ul>';
foreach($x->channel->item as $entry) {
echo '<li>';
echo '<a href="'.$entry->link.'" title="'.$entry->title.'" target="_blank">' . $entry->title . '</a>'; // output link & title
echo $entry->description; // return post content
echo '</li>';
}
echo "</ul>";
};
?>
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