如何忽略除第一次和最后一次出现之外的所有字符来执行子字符串？

Question

I try to extract a specific content. This content is the param of findTestObject function. So I built this method :

Java Code

String testObjectExtracted = line.substring(line.indexOf("(") + 1, line.indexOf(")") + 1);
String testObjectPathExtracted = StringUtils.substringBetween(testObjectExtracted, "findTestObject(", ")");
testObjectPathExtracted = testObjectPathExtracted.substring(1, testObjectPathExtracted.length() - 1);

System.out.println(line);
System.out.println(testObjectExtracted);
System.out.println(testObjectPathExtracted);

Example OK

WebUI.click(findTestObject('Menu/span_Menu'))
findTestObject('Menu/span_Menu')
Menu/span_Menu

Example KO

WebUI.click(findTestObject('Menu/Test/link (AA)'))
findTestObject('Menu/Test/link (AA)
Menu/Test/link (A
// Expected result : Menu/Test/link (AA)

However as you can see on above examples, I'm facing an problem if there is ( or ) in the path because my substring is based on ( and ) .

Do you have any solution to solve it please ? Thank you.

Answer 1

Solution is to use lastIndexOf() method.

String testObjectExtracted = line.substring(line.indexOf("(") + 1, line.lastIndexOf(")"));
String testObjectPathExtracted = testObjectExtracted.substring(testObjectExtracted.indexOf("(") + 1, testObjectExtracted.lastIndexOf(")"));
testObjectPathExtracted = testObjectPathExtracted.substring(1, testObjectPathExtracted.length() - 1);