使用ls命令隐藏不可执行的文件

Question

I'm trying to have a command that will print only the non-executable files sorted by modification time in the current directory.

What I have so far is:

$ ls -lt | grep -i "...x......"

This is printing all of the files in the dir. Just starting to learn code, any help would be much appreciated.

Answer 1

The way to go :

for file in *; do test -x "$file" || echo "$file"; done

Thanks to not parsing ls output