在具有特殊字符的python中拆分

Question

I split within a string traversing an array with values, this split must contain the following rule:

• Split the string into two parts when there is a special character, and select the first part as a result;

SCRIPT

array = [
'srv1 #s',
'srv2;192.168.9.1'
]

result = []
for x in array:

  outfinally = [line.split(';')[0] and line.split()[0] for line in x.splitlines() if line and line[0].isalpha()]

  for srv in outfinally:
      if srv != None:
          result.append(srv)

for i in result:
  print(i)

OUTPUT

srv1
srv2;192.168.9.1

DESIRED OUTPUT

srv1
srv2

Answer 1

You can split twice with the two different separators instead:

result = [s.split()[0].split(';')[0] for s in array]

result becomes:

['srv1', 'srv2']

Answer 2

The problem is here: line.split(';')[0] and line.split()[0]

Your second condition splits on whitespace. As a result, it'll always return the whitespace-split version unless there's a semicolon at the start of the input (in which case you get empty string).

You probably want to chain the two splits instead:

line.split(';')[0].split()[0]

---

To see what the code in your question is doing, take a look at what your conditional expression does in a few different cases:

array = ['srv1 s', 'srv2;192.168.9.1', ';192.168.1.1', 'srv1;srv2 192.168.1.1']

>>> for item in array:
...   print("Original: {}\n\tSplit: {}".format(item, item.split(';')[0] and item.split()[0]))
...
Original: srv1 s
        Split: srv1 # split on whitespace
Original: srv2;192.168.9.1
        Split: srv2;192.168.9.1 # split on whitespace!
Original: ;192.168.1.1
        Split: # split on special char, returned empty which is falsey, returns empty str
Original: srv1;srv2 192.168.1.1
        Split: srv1;srv2 # split only on whitespace

Answer 3

This should split on any special charters and append the first part of the split to a new list:

array = [
'srv1 #s',
'srv2;192.168.9.1'
]

sep = (r'[`\-=~!@#$%^&*()_+\[\]{};\'\\:"|<,./<>?]')
rest = text.split(sep, 1)[0]
new_array =[]
for i in array:
    new_array.append(re.split(sep,i)[0])

Output:

['srv1 ', 'srv2']

Answer 4

Change

outfinally = [line.split(';')[0] and line.split()[0] for line in x.splitlines() if line and line[0].isalpha()]

To

outfinally = [line.replace(';', ' ').split()[0] for line in x.splitlines() if line and line[0].isalpha()]

When you use and like that, it will always return the first result as long as the first result is truthy. The split function returns the full string in a list when a match is not found. Since it's returning something truthy, you'll never move on to the second condition (and if you use or like I first tried to do, you'll always move on to the second condition). Instead of having 2 conditions, what you'll have to do is combine them into one. Something like line.replace(';', ' ').split()[0] or blhsing's solution is even better.