尝试查找元素时如何在列表上使用流抛出异常？

Question

I want to throw an exception using stream when I find an element by condition

 myList.stream()
      .filter(d -> (d.getNetPrice() != new BigDecimal(0)))
      .findAny()
      .orElseThrow(
          () -> new DocumentRequestException("The product has 0 'NetPrice' as a value"));

for request

{
        "sku": "123",
        "quantity": 3,
        "description": "pc",
        "netPrice": 16806,
        "amount": 50418
    },
    {
        "sku": "1234",
        "quantity": 2,
        "description": "notebook",
        "netPrice": 0,
        "amount": 0
    }

So for that example I want the exception because the list contains one element with 'netPrice' = 0 but the code return the Pc element and nothing else happend

how can I fix it?

Answer 1

You can use anyMatch to perform an if check and throw the exception as:

if(myList.stream().anyMatch(d -> d.getNetPrice().equals(BigDecimal.ZERO)) {
    throw new DocumentRequestException("The product has 0 'NetPrice' as a value")
}