在 docker-py 中暴露网络上的端口

Question

Using the Python docker client docker-py , how do you create a container which is attached to a specific network, and exposes a specific port?

Ie the compose file may look like this:

  foo:
    ...
    expose:
      - "1234"
    networks:
      - my-network

We expose a port within my-network, without mapping it to the host.

Using docker-py's high level containers.run method only allows for Port Mappings (ie publishing ports externally) with it's ports kwarg, rather than simply exposing the port internally.
docker-py's low-level create_container method doesn't accept a simple network name to use.

How can the above compose file be replicated using docker-py?

Thanks

Answer 1

"Expose" as a verb hasn't meant much since Docker introduced multiple named Docker-internal networks. You can delete this setting from your docker-compose.yml file and it won't affect anything; other services on the same network will still be able to reach yours. That is, it should be enough to run

client.containers.run('my-image', network: 'my-network')

From what I can tell the docker-py library never supported this option (even during the time when --link was the only way to connect containers, manual --expose was never that useful). docker/docker-py#2242 asks a similar question, with a similar answer.

Answer 2

正如您在此处看到的，您可以传递主机 ip，而无需主机端口，这将使您的愿望成真。

docker.utils.create_host_config(port_bindings={1111: ('127.0.0.1',)})