将包含十六进制和 ASCII 的字符串解码为十进制

Question

I have a long string containing both hexadecimal and ASCII characters and need to convert the string into a list of individual decimal (integers) values.

All of the hexadecimal characters are contained within square brackets and I have figured out how to extract these and convert these into integers. This is shown in the code below:

# String from log file
log7 = ',[[0x8][0x1c][0x12][0x6][0xc][0x13][0xa6][0x1]a[0xc][0x9c][0x1][0xf4][0x0][0xa4][0x1][0xf7][0x1][0xa8][0x0],[0x4][0xfe][0x0][0x7][0x0][0x7][0x2][0xf0][0x7]L[0x2]u[0x0][0xa5][0x0][0xe3][0x0][0xb9][0x0]@[0x4][0xb][0x1][0x4][0x0][0x6][0x2][0x14][0x8]m[0x2]v[0x0][0xb3][0x0][0xbb][0x0][0xc5][0x0][0xa2][0xff][0x12][0x1][0x6][0x0]'

# Extract all text in square brackets and put into a list
extract = re.findall(r"\[([A-Za-z0-9_]+)\]", log7)

# Convert all hexidecimal values in list to decimal
convert = [int(x, 16) for x in extract]

# [8, 28, 18, 6, 12, 19, 166, 1, 12, 156, 1, 244, 0, 164, 1, 247, 1, 168, 0, 4, 254, 0, 7, 0, 7, 2, 240, 7, 2, 0, 165, 0, 227, 0, 185, 0, 4, 11, 1, 4, 0, 6, 2, 20, 8, 2, 0, 179, 0, 187, 0, 197, 0, 162, 255, 18, 1, 6, 0]

However, the above code does not include the ASCII characters and what I really need to do, is to convert the mix of hex and ASCII to decimals in the order they occur in the string.

I know that I can convert the individual ASCII code to decimal using:

converted_ascii = [ord(x) for x in ascii_list]

The outcome I am need is, where bold are the missing ASCII characters - from the first lot of code above:

44 , 91 , 8, 28, 18, 6, 12, 19, 166, 1, 97 ,12, 156, 1, 244, 0, 164, 1, 247, 1, 168, 0, 44 , 4, 254, 0, 7, 0, 7, 2, 240, 7, 76 , 2, 117 , 0, 165, 0, 227, 0, 185, 0, 64 , 4, 11, 1, 4, 0, 6, 2, 20, 8, 109 , 2, 118 , 0, 179, 0, 187, 0, 197, 0, 162, 255, 18, 1, 6, 0

Please, can someone offer some advice on how to get through this next step?

Answer 1

I would do

extract = re.findall(r"\[0x[0-9A-Za-z]+\]|.", log7)

convert = [ord(x) if len(x) == 1 else int(x[1:-1], 16) for x in extract]

Answer 2

Using re you can use the split function to get all those value as:

r = re.split('\[|\]',log7[2:])
values = []
for i in r:
    if i:
        try:
            values.append(int(i, 16)) # Tries to convert hex into integer
        except ValueError: # if failed it is an assci value
            values.append(ord(i)) # convert it into integer