Pymongo 提取文档，修改文档并使用 replaceone 方法更新

Question

How can I update the existing document by using python without using update mongodb query???

aa = mongodb.findByCollection(resultCollectionName, {})
totalCount = (aa.count())
count = 0
for document in aa:
    values = document["RESULTPERMONTH"].values()
    document["RESULT_SUM"] = sum(values)
    document["RESULT_AVG"] = roundTwoDigits(document["RESULT_SUM"] / len(document["RESULTPERMONTH"])) if len(document["RESULTPERMONTH"]) != 0 else -1000
    document["RESULT_LEN"] = len(document["RESULTPERMONTH"]) 
    document["RESULT_MIN"] = min(values) if len(values) != 0 else -1000
    if "buyInfo" in document:
        del document["buyInfo"]
    if "sellInfo" in document:
        del document["sellInfo"]
    try:
        mongodb.database.get_collection(resultCollectionName).save(document)
    except Exception as ex:
        print(ex)
    count = count +1
    if count % 10000 == 0:
        print(count / totalCount)

This is my previous code to update. Since save method is deprecated, I would like to replace that. But I don't want to use mongodb query but do want to use python processing.

How can I use replaceone in this case?

Answer 1

使用db.collection.replace_one() ：

db.collection.replace_one({'_id': aa['_id']}, document, upsert=True)