查找任何给定数字的第 n 位数字

Question

I'm very new to python, and I'm trying to write a program that will find the nth digit of any given positive integer from the right. How would I go about this? I'm at a bit of a loss as to where I should start. I saw an answer to a similar question suggesting code, and it seemed to work for the op. When I tried it, it just returned the number and specified digit as an ordered pair. This is that code:

def get_digit(number, n)
    return number // 10** % 10

Answer 1

This formula will give you the nth digit of a number:

def get_digit(number, n): 
     return number // 10**(n-1) % 10 

get_digit(153443, 2)                                                                                                                                                                
# 4

or by converting to string:

def get_strdigit(num, offset):
   num = str(num)
   return num[offset+1]

get_strdigit(33434324,2)                                                                                                                                                            
# '3'