如何使用列表解决此 python 问题

Question

num1 = [int(input()), int(input()), int(input()), int(input()), int(input()), int(input()), int(input())]
for i in range(0, 3):
    if num1[i] == int(8) or int(9):
        print("Ignore")
        print(num1[i])
        break

Just wondering for this code, I input 1,2,3,4,5,6,7 for the list. And it returns and prints ignore, but the for loop looping the first 4 numbers which do not equal to 8 or 9. Can someone please explain this phenomenon thanks.

Answer 1

In line 3 you say

if num1[i] == int(8) or int(9)

The problem with this is that python splits the boolean as (num[i] == int(8)) or (int(9))

int(9) is True (all non-zero numbers default to True) so your program will print("Ignore") no matter what the number is