8 位数字的正则表达式，然后是 1 个点，之后只有 2 位数字

Question

I need a regular expression for accepting eight digits and after that one dot and after that only two digits for amount fields.

Currently I'm using this much of code...

valLowLTL(val) {
    const val1 = val.split('.');
    const amountLowLTL = this.addBillingForm.get('invoicingAmtLowLTL') as FormControl;
    const re = /,/gi;
    val1[0] = val1[0].replace(re, '');
    if (val1[0].length > 8) {
      val1[0] = val1[0].substring(0, 8);
    }
    amountLowLTL.setValue(val1[0]);
    if (val1.length > 1) {
      if (val1[1].length > 2) {
        val1[1] = val1[1].substring(0, 2);
      }
      const lowValLTL = val1[0].concat('.').concat(val1[1]);
      amountLowLTL.setValue(lowValLTL);
    }
}

I just need an simple regular expression which helps me out.

Answer 1

您可以使用正则表达式： ^\\d{8}[.]\\d{2}$

Answer 2

[\d]{8}\.[\d]{2}

or

[0-9]{8}\.[0-9]{2}

https://regex101.com/r/SBAUc8/1