x86 上是否需要 std::memory_order_acquire 栅栏？

Question

Given x86 has a strong memory model, is std::memory_order_acquire fence ( not operation ) necessary?

For example, if I have this code:

uint32_t read_shm(const uint64_t offset) {
   // m_head_memory_location is char* pointing to the beginning of a mmap-ed named shared memory segment
   // a different process on different core will write to it.
   return *(uint32_t*)(m_head_memory_location + offset);
}
....
int main() {
     uint32_t val = 0;
     while (0 != (val = shm.read(some location)));
     .... // use val
}

Do I really need std::atomic_thread_fence(std::memory_order_acquire) before the return statement?

I feel it is not necessary because the goal of the code above is trying to read the first 4 bytes from m_head_memory_location + offset , and so any memory operations after fences being reordered doesn't affect the outcome.

Or there is some side effect making the acquire fence necessary?

Is there any case that an acquire fence (not operation) is necessary on x86?

Any input is welcome.

Answer 1

return *(uint32_t*)(m_head_memory_location + offset);

You cast to non- atomic non- volatile uint32_t* and dereference!!!

The compiler is allowed to assume that this uint32_t object isn't written by anything else (ie assume no data-race UB), so it can and will hoist the load out of the loop , effectively transforming it into something like if((val=load) == 0) infinite_loop(); .

• https://electronics.stackexchange.com/questions/387181/mcu-programming-c-o2-optimization-breaks-while-loop/387478#387478
• Multithreading program stuck in optimized mode but runs normally in -O0
• When to use volatile with multi threading? (never, use atomic with mo_relaxed)

A GCC memory barrier will force a reload, but this is an implementation detail for std::atomic_thread_fence(std::memory_order_acquire) . For x86, that barrier only needs to block compile-time reordering, so a typical implementation for GCC might be asm("" ::: "memory") .

It's not the acquire ordering that's doing anything, it's the memory clobber that stops GCC from assuming another read will read the same thing. That's not something ISO C++ std::atomic_thread_fence(std::memory_order_acquire) implies for non-atomic variables. (And it's always implied for atomic and volatile). So like I said, this would work in GCC but only as an implementation detail.

---

It's also strict-aliasing UB if this memory is ever accessed with other types than this an char* , or if the underlying memory was declared as a char[] array. If you got a char* from mmap or something then you're fine.

It's also possible misalignment UB unless offset is known to be a multiple of 4. (Although unless GCC chooses to auto-vectorize , this won't bite you in practice on x86.)

You can solve these two for GNU C with typedef uint32_t unaligned_u32 __attribute((may_alias, aligned(1))); but you still need volatile or atomic<T> for reading in a loop to work.

---

In general

Use std::atomic_thread_fence(std::memory_order_acquire); as required by the C++ memory model; that's what governs reordering at compile time.

When compiling for x86, it won't turn into any asm instructions; in asm it's a no-op. But if you don't tell the compiler it can't reorder something, your code might break depending on compiler optimization level.

You might get lucky and have the compiler do a non-atomic load after an atomic mo_relaxed load, or it might do the non-atomic load earlier if you don't tell it not to.