[英]Error: bad escape in Python script with regex
I am trying to do a search between lists and return the value when it matches, and when it does not.我正在尝试在列表之间进行搜索,并在匹配时返回值,当不匹配时返回值。
import re
array = ['brasil','argentina','chile','canada']
array2 = ['brasil.sao_paulo','chile','argentina']
for x,y in zip(array,array2):
if re.search('\\{}\\b'.format(x), y, re.IGNORECASE):
print("Match: {}".format(x))
else:
print("Not match: {}".format(y))
Output:输出:
Not match: brasil.sao_paulo
Not match: chile
Traceback (most recent call last):
File "main.py", line 7, in <module>
if re.search('\\{}\\b'.format(x), y, re.IGNORECASE):
File "/usr/local/lib/python3.7/re.py", line 183, in search
re.error: bad escape \c at position 0
Desired output:期望的输出:
Match: brasil
Match: argentina
Match: chile
Not match: canada
If I understand correctly, you don't need regex here.如果我理解正确,这里不需要正则表达式。
group_1 = ['brasil','argentina','chile','canada']
group_2 = ['brasil.sao_paulo','chile','argentina']
for x in group_1:
# For group 2 only, this picks out the part of the string that appears before the first ".".
if x in [y.split('.')[0] for y in group_2]:
print("Match: {}".format(x))
else:
print("Not match: {}".format(x))
which returns返回
Match: brasil
Match: argentina
Match: chile
Not match: canada
If you zip
, you'll only get pairwise matches.如果你zip
,你只会得到成对匹配。 Given the nature of your search, you can just join up the haystack into a space-delimited string and join needles into a pattern with alternation and let findall
chug away:鉴于您搜索的性质,您可以将 haystack 连接成一个以空格分隔的字符串,然后将针头连接成一个交替的模式,然后让findall
突然消失:
>>> import re
>>> needles = ['brasil', 'argentina', 'chile', 'canada']
>>> haystack = ['brasil.sao_paulo', 'chile', 'argentina']
>>> re.findall(r"\b%s\b" % "|".join(needles), " ".join(haystack), re.I)
['brasil', 'chile', 'argentina']
The intent behind \\\\
in the original regex is unclear, so I assume you want \\b
on both sides of the pattern.原始正则表达式中\\\\
背后的意图尚不清楚,因此我假设您希望在模式的两侧都使用\\b
。
A simple solution with the any
method:使用any
方法的简单解决方案:
array = ['brasil', 'argentina', 'chile', 'canada']
array2 = ['brasil.sao_paulo', 'chile', 'argentina']
for x in array:
if any(x.casefold() in y.casefold() for y in array2):
print("Match:", x)
else:
print("Not match:", x)
Edit : Using casefold()
to make it case-insensitive.编辑:使用casefold()
使其不区分大小写。
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