Bash 脚本读取文件并在每一行上卷曲并在找到字符串时输出

Question

Trying to build a shell script which determines if the site is using PulseVPN or not. The script takes a input file which contains a list of URLs, iterate each URL line by line, perform cURL operation and grep for specific string. And if string found, display a echo message "Website using PulseVPN"

Here is my code -

Keyword="dana-na" # keyword to find for PulseSecure SSL VPN
while read -r line; 
do
if curl -s -L "$line" | grep "$keyword" > /dev/null
then
    # if the keyword is in the conent
    echo " The website $line is using Pulse Secure VPN" 
else
    echo "Pulse Secure VPN Not Found on $line"
fi
done < urls.txt

Problem The code is working but The problem here is when i include only one URL in input file. It gives correct result. But if i include more than one URL in input file, then it gives incorrect results. Can anyone explains why is this happening. Is anything wrong in code ?

Answer 1

It might be skipping over the last line due to how read works. Try

while read -r line || [[ -n $line ]];

Look at this post for more information.