删除<p><br/></p>在 JavaScript 中从内容的开始和结束标记

Question

I am looking for a javascript regex through which I could remove the <p><br><p> tag from my content.

for example:

Below one is my content

<p><br></p>
<p>function removes whitespace or other predefined characters from the right side of a string.</p>
<p><br></p>
<p><br/><p>

and I am looking for this

<p>function removes whitespace or other predefined characters from the right side of a string.</p>

I am using this code but it is not working

function rtrim(str) {
  if(!str) return str;
  return str.replace(/\s+$/g, '');
}

console.log(rtrim(string));

Answer 1

You want to remove the HTML Linebreaks <br/> and its surrounding paragraph element <p> and not whitespaces, which you do with your current regex.

\\s+ matches any whitespace character (equal to [\\r\\n\\t\\f\\v ])

This should be the correct regex in your case <p><br[\\/]?><[\\/]?p>

 function rtrim(str) { if(!str) return str; return str.replace(/<p><br[\\/]?><[\\/]?p>/g, ''); } console.log(rtrim("<p><br></p><p>function removes whitespace or other predefined characters from the right side of a string.</p><p><br></p><p><br/><p>"));

I used <br[\\/]?> to make sure both linebreaks with and without a forward slash will match.

Answer 2

Instead of replacing <p><br></p> , You can extract only <p>some text</p> .

For example like below,

let a = "<p><br></p><p>function removes whitespace or other predefined characters from the right side of a string.</p><p><br></p><p><br/><p>";
a = /(<p>[^<>].*[^<>]<\/p>)/g.exec(a)[0];
console.log(a); // "<p>function removes whitespace or other predefined characters from the right side of a string.</p>"

Answer 3

If you need specifically a RegExp I would suggest the answer posted by Red .

If you are not required to use a RegExp, you could split by line and filter that string, then join it again,
although this example will only work if they are separated by \\n :

function rtrim(str) {
  if(!str) return str;
  return str
    .split('\n')
    .filter((s) => s === '<p><br></p>')
    .join('\n');
}