[英]using mutate_at with the in operator %in%
I have a data frame with a few variables to reverse code.我有一个带有一些变量的数据框来反转代码。 I have a separate vector that has all the variables to reverse code.我有一个单独的向量,其中包含要反转代码的所有变量。 I'd like to use mutate_at(), or some other tidy way, to reverse code them all in one line of code.我想使用 mutate_at() 或其他一些整洁的方式,在一行代码中对它们进行反向编码。 Here's the dataset and the vector of items to reverse这是数据集和要反转的项目向量
library(tidyverse)
mock_data <- tibble(id = 1:5,
item_1 = c(1, 5, 3, 5, 5),
item_2 = c(4, 4, 4, 1, 1),
item_3 = c(5, 5, 5, 5, 1))
reverse <- c("item_2", "item_3")
Here's what I want it to look like with only items 2 and 3 reverse coded:这是我希望它看起来像只有第 2 项和第 3 项反向编码:
library(tidyverse)
solution <- tibble(id = 1:5,
item_1 = c(1, 5, 3, 5, 5),
item_2 = c(2, 2, 2, 5, 5),
item_3 = c(1, 1, 1, 1, 5))
I've tried this below code.我试过下面的代码。 I know that the recode is correct because I've used it for other datasets, but I know something is off with the %in% operator.我知道重新编码是正确的,因为我已经将它用于其他数据集,但我知道 %in% 运算符有问题。
library(tidyverse)
mock_data %>%
mutate_at(vars(. %in% reverse), ~(recode(., "1=5; 2=4; 3=3; 4=2; 5=1")))
Error: `. %in% reverse` must evaluate to column positions or names, not a logical vector
Any help would be appreciated!任何帮助,将不胜感激!
You can give reverse
directly to mutate_at
, no need for vars(. %in% reverse)
.你可以直接给mutate_at
reverse
,不需要vars(. %in% reverse)
。 And I would simplify the reversing as 6 minus the current value.我会将反向简化为 6 减去当前值。
mock_data %>% mutate_at(reverse, ~6 - .)
# # A tibble: 5 x 4
# id item_1 item_2 item_3
# <int> <dbl> <dbl> <dbl>
# 1 1 1 2 1
# 2 2 5 2 1
# 3 3 3 2 1
# 4 4 5 5 1
# 5 5 5 5 5
If there's a possibility that reverse
includes columns that are not in mock_data
, and you want to skip those, use mutate_at(vars(one_of(reverse)), ...)
如果reverse
可能包含不在mock_data
列,并且您想跳过这些列,请使用mutate_at(vars(one_of(reverse)), ...)
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