使用复选框从一个表中删除行数据并将删除的行数据插入另一个表中

Question

/*I have two table , 1st table name is bazar and 2nd table name is bazarduepayment having same columne name : sl,date,item,paid,due,remark. /*我有两个表，第一个表名是bazar，第二个表名是bazarduepayment，列名相同：sl,date,item,paid,due,remark。 'sl' is auto increment . 'sl' 是自动增量。 Delete function is working perfectly .删除功能运行良好。 Someone please help me how to insert deleted row data in 2nd table 'bazarduepayment' Here below is code detail i wrote */有人请帮助我如何在第二个表“bazarduepayment”中插入已删除的行数据下面是我写的代码详细信息*/

<?php
session_start();
include_once("rwdbconnection.php");
error_reporting(0);

if(isset($_POST['save']))
 {
   $checkbox = $_POST['check'];
   for($i=0;$i<count($checkbox);$i++)
    {
    $del_id = $checkbox[$i]; 
    mysqli_query($conn,"DELETE FROM bazar WHERE sl='".$del_id."'");
    $message = "Data deleted successfully !";

   }
   }
    $result = mysqli_query($conn,"SELECT * FROM bazar");
    ?>

<!DOCTYPE html>
<html>
<head>
        <linkrel="stylesheet"href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/css/bootstrap.min.css">
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.2.1/jquery.min.js"></script>
<title>Delete data</title>
 </head>
  <body>

   <div>
   <?php if(isset($message)) { echo $message; } ?>
   </div>

   <form method="post" action="">
   <table class="table table-bordered">
   <thead>
   <tr>
   <th><input type="checkbox" id="checkAl"> Select All</th>
   <th>Sl</th>
   <th>Date</th>
   <th>Item</th>
   <th>Paid</th>
   <th>Due</th>
   <th>Remark</th>
   </tr>
   </thead>
   <?php
        $i=0;
        while($row = mysqli_fetch_array($result)) 
        {
        ?>
        <tr>
        <td><input type="checkbox" id="checkItem" name="check[]" value="<?php echo $row["sl"]; ?>"></td>
        <td><?php echo $row["sl"]; ?></td>
        <td><?php echo $row["date"]; ?></td>
        <td><?php echo $row["item"]; ?></td>
        <td><?php echo $row["paid"]; ?></td>
        <td><?php echo $row["due"]; ?></td>
        <td><?php echo $row["remark"]; ?></td>
        </tr>
        <?php
        $i++;
        }
        ?>
        </table>
        <p align="center"><button type="submit" class="btn btn-success" name="save">DELETE</button></p>
        </form>
        <script>
        $("#checkAl").click(function () {
        $('input:checkbox').not(this).prop('checked', this.checked);
        });
        </script>
        </body>
        </html>

Answer 1

First you need to copy the data from one table to another using INSERT ... SELECT syntax and only then you can delete.首先，您需要使用INSERT ... SELECT语法将数据从一个表复制到另一个表，然后才能删除。

You should be using prepared statements for this.您应该为此使用准备好的语句。

if (isset($_POST['save'])) {
    // Prepared INSERT query
    $stmt_insert = $conn->prepare('INSERT INTO bazarduepayment(date,item,paid,due,remark) 
        SELECT date,item,paid,due,remark FROM bazar WHERE sl=?');

    // Prepare DELETE query
    $stmt_delete = $conn->prepare('DELETE FROM bazar WHERE sl=?');

    // Loop on all checkboxes selected
    foreach ($_POST['check'] as $del_id) {
        $stmt_insert->bind_param('s', $del_id);
        $stmt_insert->execute();

        $stmt_delete->bind_param('s', $del_id);
        $stmt_delete->execute();
    }
}

You could even simplify this to get rid of the foreach loop entirely.您甚至可以简化它以完全摆脱foreach循环。

使用复选框从一个表中删除行数据并将删除的行数据插入另一个表中

问题描述

1 个解决方案

解决方案1
-1 2019-12-26 14:41:45

使用复选框从一个表中删除行数据并将删除的行数据插入另一个表中

问题描述

1 个解决方案

解决方案1 -1 2019-12-26 14:41:45

解决方案1
-1 2019-12-26 14:41:45