如何在 Python 中找到列表的中间元素/索引？

Question

I want to be able to print the middle element of a list . The list might be just strings, integers or mixed. I tried this, by finding the index of the middle element, but doesn't work. (It prints 2)

list = [1,3,7,"this",3,"that",7]

if int(len(list))<2:
  middle = 1  // if it has less than 2 entries, the first entry is the middle one. 

elif int(len(list)) %2 == 0 :
  middle = int(len(list)/2)

else: 
  middle = int((len(list)/2) - 1)

print(list[middle])

Answer 1

In case you want to round down for odd amount of list elements, you can use math.trunc for all cases:

l = [1,3,7,"this",3,"that",7]
middle = math.trunc(len(l)/2)
print(middle)
>>> 3

Answer 2

You cannot use list as a variable name, it is already reserved. Second, comments in python should be like this # comment not //comment .

The following code works just fine:

listt = [1,3,7,"this",3,"that", 7]
middle = int((len(listt)/2)) 
print(listt[middle])