从文件路径中提取所需的目录名称

Question

I have the path-name of a file as follows:

fi = "http://pen.jamstec.go.jp/TKC_/public_html/original/dc/dc_2008/dc_2008_141/dc_2008_141_0706+0900_TKC__y30_u.jpg"

How can I extract "TKC_" as the required information?

I tried as print (os.path.basename(fi)) but it printed:

dc_2008_141_0706+0900_TKC__y30_u.jpg

"http://pen.jamstec.go.jp/**TKC_**/public_html/original/dc/dc_2008/dc_2008_141/dc_2008_141_0706+0900_TKC__y30_u.jpg"

Answer 1

Try

from urllib.parse import urlparse

fi = "http://pen.jamstec.go.jp/TKC_/public_html/original/dc/dc_2008/dc_2008_141/dc_2008_141_0706+0900_TKC__y30_u.jpg"
urlparse(fi).path.split('/')[1]

Answer 2

Try using regex:

import re
fi = "http://pen.jamstec.go.jp/TKC_/public_html/original/dc/dc_2008/dc_2008_141/dc_2008_141_0706+0900_TKC__y30_u.jpg"
result = re.search(r'http://.*?/(.*?)/',fi)
print(result.group(1))

Answer 3

You can use Regex to define a pattern to search for in a string, which is TKC_ in this case.

import re
fi = "http://pen.jamstec.go.jp/TKC_/public_html/original/dc/dc_2008/dc_2008_141/dc_2008_141_0706+0900_TKC__y30_u.jpg"
httpObj = re.compile(r'TKC_') # pattern to search for in the string
print(httpObj.findall(fi)[0])

If you remove [0] in the print() statement it will get you a list of all occurrences of TKC_ in the string.