如何遍历pandas df列，查找字符串是否包含来自单独的pandas df列的任何字符串？

Question

I have two pandas DataFrames in python. DF A contains a column, which is basically sentence-length strings.

|---------------------|------------------|
|        sentenceCol  |    other column  |
|---------------------|------------------|
|'this is from france'|         15       |
|---------------------|------------------|

DF B contains a column that is a list of countries

|---------------------|------------------|
|        country      |    other column  |
|---------------------|------------------|
|'france'             |         33       |
|---------------------|------------------|
|'spain'              |         34       |
|---------------------|------------------|

How can I loop through DF A and assign which country the string contains? Here's what I imagine DF A would look like after assignment...

|---------------------|------------------|-----------|
|        sentenceCol  |    other column  | country   |
|---------------------|------------------|-----------|
|'this is from france'|         15       |  'france' |
|---------------------|------------------|-----------|

One additional complication is that there can be more than one country per sentence, so ideally this could assign every applicable country to that sentence.

|-------------------------------|------------------|-----------|
|        sentenceCol            |    other column  | country   |
|-------------------------------|------------------|-----------|
|'this is from france and spain'|         16       |  'france' |
|-------------------------------|------------------|-----------|
|'this is from france and spain'|         16       |  'spain'  |
|-------------------------------|------------------|-----------|

Answer 1

There's no need for a loop here. Looping over a dataframe is slow and we have optimized pandas or numpy methods for almost all of our problems.

In this case, for your first problem , you are looking for Series.str.extract :

dfa['country'] = dfa['sentenceCol'].str.extract(f"({'|'.join(dfb['country'])})")

           sentenceCol  other column country
0  this is from france            15  france

---

For your second problem , you need Series.str.extractall with Series.drop_duplicates & to_numpy :

dfa['country'] = (
    dfa['sentenceCol'].str.extractall(f"({'|'.join(dfb['country'])})")
        .drop_duplicates()
        .to_numpy()
)

                     sentenceCol  other column country
0  this is from france and spain            15  france
1  this is from france and spain            15   spain

---

Edit

Or if your sentenceCol is not duplicated, we have to get the extracted values to a single row. We use GroupBy.agg :

dfa['country'] = (
    dfa['sentenceCol'].str.extractall(f"({'|'.join(dfb['country'])})")
        .groupby(level=0)
        .agg(', '.join)
        .to_numpy()
)

                     sentenceCol  other column        country
0  this is from france and spain            15  france, spain

---

Edit2

To duplicate the original rows. We join the dataframe back to our extraction:

extraction = (
    dfa['sentenceCol'].str.extractall(f"({'|'.join(dfb['country'])})")
        .rename(columns={0: 'country'})
)

dfa = extraction.droplevel(1).join(dfa).reset_index(drop=True)

  country                    sentenceCol  other column
0  france  this is from france and spain            15
1   spain  this is from france and spain            15

---

Dataframes used:

dfa = pd.DataFrame({'sentenceCol':['this is from france and spain']*2,
                   'other column':[15]*2})

dfb = pd.DataFrame({'country':['france', 'spain']})

Answer 2

You can iterate through a dataframe with the method iterrows() . You can try this:

# Dataframes definition
df_1 = pd.DataFrame({"sentence": ["this is from france and spain", "this is from france", "this is from germany"], "other": [15, 12, 33]})
df_2 = pd.DataFrame({"country": ["spain", "france", "germany"], "other_column": [7, 7, 8]})


# Create the new dataframe
df_3 = pd.DataFrame(columns = ["sentence", "other_column", "country"])
count=0

# Iterate through the dataframes, first through the country dataframe and inside through the sentence one.
for index, row in df_2.iterrows():
    country = row.country

    for index_2, row_2 in df_1.iterrows():
        if country in row_2.sentence:
            df_3.loc[count] = (row_2.sentence, row_2.other, country)
            count+=1

So the output is:

sentence                            other_column    country
0   this is from france and spain   15              spain
1   this is from france and spain   15              france
2   this is from france             12              france
3   this is from germany            33              germany