此查询替换为 Laravel。 在laravel中怎么写？

Question

select u.name,GROUP_CONCAT( DISTINCT c.category_name SEPARATOR ',') AS category_name FROM users as u 
INNER JOIN category as c ON FIND_IN_SET(c.id, u.cate) 
GROUP BY u.id

Answer 1

 User::with('category'=>function($q){
     $q->select( DB::raw("GROUP_CONCAT( DISTINCT c.category_name SEPARATOR ',') AS category_name"))->whereRaw("find_in_set(c.id, user.cate)")
    })->groupBy("user.id")->get();

or you can simply use for any query you have

DB::select( DB::raw("select u.name,GROUP_CONCAT( DISTINCT c.category_name SEPARATOR ',') AS category_name FROM users as u 
INNER JOIN category as c ON FIND_IN_SET(c.id, u.cate) 
GROUP BY u.id));

Answer 2

With query builder you can do It un this way

$data = User::select('users.name')
             ->selectRaw("GROUP_CONCAT( DISTINCT category.category_name SEPARATOR ',') AS category_name")
             ->join('category', 'category.id', '=', 'users.cate')
             ->groupBy('users.name')
             ->get();

Use:

• selectRaw for running pure sql queries
• Use innerJoin to link two tables
• Use groupBy for grouping results this because you're using GROUP_CONCAT
• In spite of using table users name i do prefer yo invoke the model name related to It
• Only check in my example table AND column names

Another option use Laravel relationships but for this you will need

• Model for every table
• belongsTo and hasMany methods created ay your model classes

Also Is neccesary you keep in mind

You need to GROUP BY for every column in your SELECT statment because:

• It's part of standar
• Laravel comes with strict mode enabled
• Except MySQL, every SQL engine Will throw an error if you dont do this
• Here the MySQL docs. where you can read more about it, because your group is wrong