从包含某些字符的列表中删除单词

Question

I have a long list of words that I'm trying to go through and if the word contains a specific character remove it. However, the solution I thought would work doesn't and doesn't remove any words

l3 = ['b', 'd', 'e', 'f', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y']


firstcheck = ['poach', 'omnificent', 'aminoxylol', 'teetotaller', 'kyathos', 'toxaemic', 'herohead', 'desole', 'nincompoophood', 'dinamode']

validwords = []

for i in l3:
    for x in firstchect:
        if i not in x:
            validwords.append(x)
            continue
        else:
            break

If a word from firstcheck has a character from l3 I want it removed or not added to this other list. I tried it both ways. Can anyone offer insight on what could be going wrong? I'm pretty sure I could use some list comprehension but I'm not very good at that.

Answer 1

接受的答案使用np.sum这意味着导入一个巨大的数字库来执行 Python 内核可以轻松完成的简单任务：

validwords = [w for w in firstcheck if all(c not in w for c in l3)]

Answer 2

you can use a list comprehension:

import numpy as np
[w for w in firstcheck if np.sum([c in w for c in l3])==0]

It seems all the words contain at least 1 char from l3 and the output of above is an empty list.

If firstcheck is defined as below:

firstcheck = ['a', 'z', 'poach', 'omnificent']

The code should output:

['a', 'z']

Answer 3

Ah, there was some mistake in code, rest was fine:

l3 = ['b', 'd', 'e', 'f', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y']


firstcheck = ['aza', 'ca', 'poach', 'omnificent', 'aminoxylol', 'teetotaller', 'kyathos', 'toxaemic', 'herohead', 'desole', 'nincompoophood', 'dinamode']

validwords = []
flag=1
for x in firstcheck:
    for i in l3:
        if i not in x:
            flag=1
        else:
            flag=0  
            break
    if(flag==1):
        validwords.append(x)   

print(validwords)

So, here the first mistake was, the for loops , we need to iterate through words first then, through l3, to avoid the readdition of elements.

Next, firstcheck spelling was wrong in 'for x in firstcheck` due to which error was there.

Also, I added a flag, such that if flag value is 1 it will add the element in validwords. To, check I added new elements as 'aza' and 'ca' , due to which, now it shows correct o/p as 'aza' and 'ca'.

Hope this helps you.

Answer 4

If you want to avoid all loops etc, you can use re directly.

import re
l3 = ['b', 'd', 'e', 'f', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y']
firstcheck = ['azz', 'poach', 'omnificent', 'aminoxylol', 'teetotaller', 'kyathos', 'toxaemic', 'herohead', 'desole', 'nincompoophood', 'dinamode']

# Create a regex string to remove.
strings_to_remove = "[{}]".format("".join(l3))
validwords = [x for x in firstcheck if re.sub(strings_to_remove, '', x) == x]
print(validwords)

Output:

['azz']