Select * From Table Where Name in like（通配符）

Question

Is it possible to combine SQL statements such as

SELECT * FROM X WHERE Y LIKE '%a%' OR Y LIKE '%b%' OR Y LIKE '%c%' OR Y LIKE '%d%'

with something like

SELECT * FROM X WHERE Y IN ('a', 'b', 'c', 'd')

so I don't have to write one big statement such as it is now:

IF NOT EXISTS(SELECT * FROM X WHERE Y LIKE '%a%' OR Y LIKE '%b%' OR Y LIKE '%c%' OR Y LIKE '%d%')
    BEGIN
        /* code */
    END

Would be very nice to use something like SELECT * FROM X WHERE Y IN LIKE ('%a%', '%b%', etc..) Appreciate all help and suggestions, thanks.

Answer 1

请使用以下代码解决您的问题，如果仍有问题，请尝试让我知道。

SELECT * FROM X WHERE Y LIKE '%[a-d]%'

Answer 2

If your database supports RegEx, you can use that. For example:

SELECT * FROM X WHERE Y SIMILAR TO '%(a|b|c|d)%' in PostgreSQL, and

SELECT * FROM X WHERE Y REGEXP 'a|b|c|d' in MySQL.

LIKE '%[ad]%' won't work because LIKE s in most databases don't accept regex patterns. This will just expect the literal text [ad] somewhere in the string. How each database interprets regular expression (or native pattern) varies a lot. So you need to tailor these things to your database. For example, the following will not work in PostgreSQL:

SELECT * FROM X WHERE Y SIMILAR TO 'a|b|c|d'

because PostgreSQL will expect the whole string to be 'a', 'b', 'c', or 'd'.