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在链表中重载运算符 <<

[英]Overloading operator << in linked list

I'm currently in the middle of my studies on university and I'm struggling to finish my current project.我目前正在大学学习中,我正在努力完成我目前的项目。 The assignment was to creat a linked list that will store number bigger than integer and add functions that will do some simple operations like <<,>>,+,-.任务是创建一个链接列表,该列表将存储大于整数的数字并添加将执行一些简单操作的函数,例如 <<、>>、+、-。 While I have the whole linked list worked out I'm struggling to think how to overload operator << and >>.虽然我已经计算出整个链表,但我正在努力思考如何重载运算符 << 和 >>。 I tried few thing, googled it out but no solution actually solves my problem.我尝试了几件事,用谷歌搜索,但没有解决方案真正解决我的问题。 General idea was to take a number as string then divide it into many 1digit numbers and put it into my list but without working << I can't even start.一般想法是将一个数字作为字符串,然后将其分成许多 1 位数字并将其放入我的列表中,但没有工作<<我什至无法开始。 My list.h我的清单.h

#ifndef LISTA_H_INCLUDED
#define LISTA_H_INCLUDED
#include <iostream>
using namespace std;

struct List {
    private:
        struct Node {
            int data;
            Node *next;
            Node(int _data, Node *_next = NULL) {
                data = _data;
                next = _next;
            }
        };
        Node *head, *tail;
        int counter;
        public:
        List();
        ~List();
        friend ostream& operator<<(ostream& wyjscie,const List& L);
        //friend ostream& operator>>(ostream& wejscie,const List& L);
        //customowe funkcje
};

#endif // LISTA_H_INCLUDED

and list.cpp和 list.cpp

#include "lista.h"

List::List()
{
    head = NULL;
    tail = NULL;
    counter = 0;
}

List::~List()
{
    while(head != NULL)
    {
        Node *killer = head;
        head = head -> next;
        delete killer;
    }
    tail = NULL;
    counter = 0;
}
ostream& operator<<(ostream& wyjscie,const List& L)
{
    Node *temp;
    for(temp = L.head; temp != 0; temp = temp -> next)
    {
        wyjscie << temp -> data;
        wyjscie<<endl;
    }
    return wyjscie;
}

Problem is that Node is not declared in this scope and when I try to do it without this temporary Node I'm also failing since list is const.问题是 Node 未在此范围内声明,当我尝试在没有此临时 Node 的情况下执行此操作时,我也失败了,因为 list 是 const。 Thanks in advance for any tips.提前感谢您的任何提示。

EDIT编辑

First problem solved.第一个问题解决了。 I moved to overloading operator>>.我转向重载运算符>>。 I created and insert(string a) function which takes the string, divides it and inserts into the linked list.我创建了 insert(string a) 函数,它接受字符串,将其分割并插入到链表中。 After doing that I thought that overloading operator>> will be just using that function.这样做之后,我认为重载 operator>> 将只是使用该函数。 I'm not sure why it's not working.我不确定为什么它不起作用。

void List::insert(string a)
{
    int n=a.size();
    for(int i=0;i<n;++i)
    {
    Node *nowy=new Node(a[i]);
    if(head==nullptr)
    {
        head=nowy;
        tail=nowy;
    }
    else
    {
        (*tail).next=nowy;
        tail=nowy;
    }
    }
}
istream& operator>>(istream& wejscie,const List& L)
{
    wejscie >> List::insert(string a);
    return wejscie;
}

I also tried something like this:我也尝试过这样的事情:

istream& operator>>(istream& wejscie,const List& L)
{
    string a;
    cin >>a;
    wejscie >> L.insert(a);
    return wejscie;
}

My main function我的主要功能

#include "lista.h"
int main()
{
    List T1;
    List T2;
    T1.insert("54321");
    cout << T1 << endl;
    cin >> T2;
    cout << T2;

}

The function功能

ostream& operator<<(ostream& wyjscie,const List& L)

is not linked to the List class, so List should be specified to use Node in that.未链接到List类,因此应指定List以在其中使用Node

In other words, you should use List::Node *temp;换句话说,你应该使用List::Node *temp; instead of Node *temp;而不是Node *temp; . .

For EDIT part对于编辑部分

Why your programs won't work:为什么您的程序不起作用:

istream& operator>>(istream& wejscie,const List& L)
{
    // List::insert isn't telling which list to insert
    // "string a" here is invalid syntax
    wejscie >> List::insert(string a);
    return wejscie;
}
// L is const, so insertion won't be accepted
istream& operator>>(istream& wejscie,const List& L)
{
    string a;
    // cin suddenly appeared from somewhere
    cin >>a;
    // return type of L.insert(a) is void, so it won't suit for operand of >> operator
    wejscie >> L.insert(a);
    return wejscie;
}

(my guess of) What you should do is: (我的猜测)你应该做的是:

  1. read a string from wejsciewejscie读取一个字符串
  2. "insert" it to L “插入”它到L

An implementation of that:一个实现:

istream& operator>>(istream& wejscie,List& L)
{
    string a;
    wejscie >> a;
    L.insert(a);
    return wejscie;
}

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