为什么我在这段代码中得到 Input MIsmatch Exception？

Question

I am just trying to read integer, double , string values from keyboard. it just working fine for integer and double. but when it comes to string, it was throwing a Input Mismatch Exception, so i cant able to read string from keyboard.

import java.util.Scanner;
import java.util.*;

public class Solution {

    public static void main(String[] args) {
        Scanner scan = new Scanner(System.in);
        int i = scan.nextInt();
        double d= scan.nextInt();
        String s=scan.nextLine();

        // Write your code here.

        System.out.println("String: " + s);
        System.out.println("Double: " + d);
        System.out.println("Int: " + i);
    }
}

Answer 1

You have used double d= scan.nextInt();

instead use

double d= scan.nextDouble();

Moreover String is working fine for following input and output: 1 1 Hello

String: Hello

Double: 1.0

Int: 1

Answer 2

First, you're doing a scan.nextInt() for a double. Not the best thing to do. Second, try scan.next() to get an arbitrary type token.

        int i = scan.nextInt();
        double d= scan.nextDouble();
        String s=scan.next();

Answer 3

please check the below code. it is working for me.

      public class Solution {

    public static void main(String[] args) {

        Scanner scan = new Scanner(System.in);
        System.out.println("enter i value ");
        int i = scan.nextInt();
        System.out.println("enter d value ");
        double d= scan.nextDouble();
        System.out.println("enter s value ");
        String s=scan.next();


        // Write your code here.

        System.out.println("String: " + s);
        System.out.println("Double: " + d);
        System.out.println("Int: " + i);
    }

}

Answer 4

I think String s=scan.nextLine(); consumes the newline character coming from the followed calling double d= scan.nextInt(); .

Here is my two cents.

double d = scan.nextInt();
scan.nextLine();
String s = scan.nextLine();