如何添加两个包含十六进制数字的字符串而不将它们转换为 int？

Question

I have a hexadecimal number in a String which is to large to convert to int and long and want to add the value of another hexadecimal number. So let's say I have this number:

String hex1 = "0xf27f2029f9c103f77be78b9591c1ab27167858d27d789cd3ea8a270c67ea5d91";

And want to add:

int hex2 = 0x1;  or  String hex2 = "0x1";

I know this question has been asked allready How to subtract or add two hexadecimal value in java but the answers don't work for me because they all involve conversion to int.

Answer 1

You can do it as follows:

import java.math.BigInteger;

public class Main {
    public static void main(String[] args) {
        String hex1 = "0xf27f2029f9c103f77be78b9591c1ab27167858d27d789cd3ea8a270c67ea5d91";
        String hex2 = "0x1";
        System.out.println(
                "In decimal: " + new BigInteger(hex1.substring(2), 16).add(new BigInteger(hex2.substring(2), 16)));
        System.out.println("In hexdecimal: "
                + new BigInteger(hex1.substring(2), 16).add(new BigInteger(hex2.substring(2), 16)).toString(16));
    }
}

Output:

In decimal: 109684320921920394042076832992416841330182602685967688614501993994243850001810
In hexdecimal: f27f2029f9c103f77be78b9591c1ab27167858d27d789cd3ea8a270c67ea5d92

Answer 2

Change your code to:

String hex1="0xf27f2029f9c103f77be78b9591c1ab27167858d27d789cd3ea8a270c67ea5d91";
int hex2=0x1;
string hex2="0x1";

You need "" for entering a value for string.