c - 如何将char *指针分配给c中的char变量

Question

I have a struct Track with variable like this char artist[81];

I have a function to create a new track Track *newTrack(char *artist, char *title, int time);

But doing this is not possible..

track->artist = artist;

How can I transform a char array into a char?

Answer 1

you can use strcpy ,

    strcpy(track->artist, artist);

include header

      #include<string.h>

Answer 2

In this case you can use strcpy in this way:

strcpy(track->artist, artist);

but pay attention:

To avoid overflows, the size of the array pointed by destination shall be long enough to contain the same C string as source (including the terminating null character), and should not overlap in memory with source.

for more details i leave you a useful link : strcpy