在 Java 中使用 xpath 从节点列表中获取属性

Question

XML

    <Employees>
<Employee id="1" name="xyz">
<Employee id="2" name="abc">
</Employees>

I can get the list of Employee node with xpath expression

XPathExpression expr=xpath.compile("/Employees/Employee");
            NodeList nodes = (NodeList) expr.evaluate(doc, XPathConstants.NODESET);

How to get the attributes id, name from each node in the list.

Answer 1

尝试将您的 xpath 表达式更改为

/Employees/Employee/@id

Answer 2

You cannot ask a single list returning 2-tuples of (id, name) But you can have this in two separate node lists:

XPathExpression expr1 = xpath.compile("/Employees/Employee/@id");
NodeList nodes1 = (NodeList) expr1.evaluate(doc, XPathConstants.NODESET);

XPathExpression expr2 = xpath.compile("/Employees/Employee/@name");
NodeList nodes2 = (NodeList) expr2.evaluate(doc, XPathConstants.NODESET);

However, if having a single list is such important, some workaround are possible, for instance by concatenating both attributes values into a csv-like string:

XPathExpression expr = xpath.compile("concat(/Employees/Employee/@id, ';', /Employees/Employee/@name)");

which will return a list of 2 nodes:

"1;xyz"
"2;abc"