从斐波那契数列 C++ 中的数组中找到正确的元素时出错

Question

So i am changed the code a little bit. It still doesn't work but i think i am little bit closer. The program should check if the number you put in (inside bar[100]) match the fibonacci numbers(stored in fib[30]) and then print the ones that match.

#include <iostream>
#include <math.h>

using namespace std;

int main() {
    long x, bar[100], fib[30];

    cout << "Cate numere sunt in array? = ";
    cin >> x;
        for (int i = 0; i < x; i++) {
            cout << "bar[" << i << "]=";
            cin >> bar[i];
            }

    fib[0] = 1;
    fib[1] = 1;
    fib[2] = 2;
        for (int i = 3; i <= 30; i++) {

            fib[i] = fib[i - 2] + fib[i - 1];
        //  cout << fib[i] << " ";
        }
        for (int i = 0; i < x; i++) {
            bool fibonacci = false;
            int j = 0;
                while (j < 30  && !fib) {
                // the mistake is here ( ' || ' instead of ' && ')
                    if (fib[j] == bar[i]) {
                        fibonacci = true;
                        }
                    j++;
                }
                if (fibonacci) {
                    cout << bar[i] << " ";
            }
    }


return 0;
}```

Answer 1

The code above works pretty well for me. It prints out every right number of the Fibonacci sequence you introduce in the bar[100] array. Special thanks to @PaulMcKenzie and everyone who helped!

Answer 2

Move the bar[1] bar[2] and bar[3] initialization outside of the for loop. They are not defined outside the scope of it.