如何在记事本++中删除数字之间的文本

Question

I have texts like

3.6. Sam
3.7. Willy

4.1. drake
4.2. nadeem

I need output like

3-6 Sam
3-7 Willy

4-1 drake
4-2 nadeem

I tried replace \\d{1}.\\d{1}. with \\d{1}-\\d{1} & later with $1-$2

But I cant retain the number. Can anyone help me with this

Answer 1

Use the following Regex:

(\d)\.(\d)\.

And replace with:

$1-$2

You were going wrong because you need capture groups around the numbers. (\\d) instead of just \\d .

And you don't need to specify {1} if it's just one, you can leave that out. Also you put . but that represents any character, not just the period/fullstop, for that you have to escape it with a slash as \\. .

Answer 2

• Ctrl + H
• Find what: ^(\\d+)\\.(\\d+)\\.
• Replace with: $1-$2
• CHECK Wrap around
• CHECK Regular expression
• UNCHECK . matches newline . matches newline
• Replace all

Explanation:

^       # beginning of line
  (\d+) # group 1, 1 or more digits
  \.    # a dot
  (\d+) # group 2, 1 or more digits
  \.    # a dot

Screen capture (before):

Screen capture (after):

Answer 3

Another option is to make use of \\K and use a single group in the replacement.

Find what:

\d\K\.(\d)\.

Replace with:

-$1

Explanation

• \\d Match a single digit (use \\d+ to match 1 or more digits)
• \\K Reset starting point of the reported match (forget what was matched)
• \\.(\\d)\\. Capture a digit in group 1 between matching a dot on the left and right

Regex demo

If all your matches are at the start of the string, you prepend a ^ to the pattern.

Answer 4

A shortest forum of regex will look like this...
Find what: \\.(\\d)\\.
Replace with: -$1 or ↝ -\\1